Aaeeschylus could you please try your Hanjies before posting them to see if they can be solved - there are quite a few you have done that have involved guessing. Thanks.

Any Hints on this one?

Pointless and impossible. Do you understand what Hanjie is? A logic puzzle. It is not guess who!!!

It´s completely logical :)
HINT: Turn your attention to 2 top lines - there´s only one way to arrange all those 2s and 1s.

I did it but i don't know how to give hints on this one!
I have to just give the answer! lol

Line 1 : BB XX BB XX BB XX BB X (B= Black and X is empty)
Line 10: B X B X B XX BB X B X B X B
Line 15: X BB XX BB XX BB XX BB

Hope this helps!

Joe is quite right - totally logical, start with top two rows, or bottom two, or left two columns, or right two. Same applies. Only one configuration will allow you to get fit the third row.

You don't even need to think about how things work together. Do it like a normal hanji - there's a perfectly usable starting point with the 1 1 1 2 1 1 1 rows. Complete from there.

Logical.

I have to agree with FortunaDraken.
If you want to puzzle some lines, you have to consider the first three rows - only two (like Joe Tramp said) is not enough, because there are several options - but only one that fits row three.

I posted my comments on the wrong puzzle - this one is logical but I just wanted to give the tip of trying before posting. My earlier Hanjies are terrible because my lack of solving skills so always like to give tips to anyone who starts the same way as me!!!

My comments should have been posted on the 4 pokeball pattern.

I didn't have to guess once. You can also start with the 2's in the long rows.

I take back my earlier comment. This one is solvable without guessing.

One of the smartest puzzles on here. Kudos!

Well, I did use Chano's hint but only for line 1. I know I didn't need anything else after that anyway.

Chano I made it with your first line hint... Tnx.

Thank you for indicating the puzzle is logical, FortunaDraken. Wouldn't have thought it was otherwise.